(4x+5)(x^2-2x+1)=0

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Solution for (4x+5)(x^2-2x+1)=0 equation: 


Simplifying
(4x + 5)(x2 + -2x + 1) = 0

Reorder the terms:
(5 + 4x)(x2 + -2x + 1) = 0

Reorder the terms:
(5 + 4x)(1 + -2x + x2) = 0

Multiply (5 + 4x) * (1 + -2x + x2)
(5(1 + -2x + x2) + 4x * (1 + -2x + x2)) = 0
((1 * 5 + -2x * 5 + x2 * 5) + 4x * (1 + -2x + x2)) = 0
((5 + -10x + 5x2) + 4x * (1 + -2x + x2)) = 0
(5 + -10x + 5x2 + (1 * 4x + -2x * 4x + x2 * 4x)) = 0
(5 + -10x + 5x2 + (4x + -8x2 + 4x3)) = 0

Reorder the terms:
(5 + -10x + 4x + 5x2 + -8x2 + 4x3) = 0

Combine like terms: -10x + 4x = -6x
(5 + -6x + 5x2 + -8x2 + 4x3) = 0

Combine like terms: 5x2 + -8x2 = -3x2
(5 + -6x + -3x2 + 4x3) = 0

Solving
5 + -6x + -3x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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